A plane electromagnetic wave of angular frequ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The conduction current density is given by $J_c = \sigma E$,where $E = E_0 \sin(\omega t - kx)$. Thus,the magnitude is $J_c = \sigma E_0$.The disp

Vedclass · Accepted Answer

$\frac{\sigma}{\varepsilon \varepsilon_0 \omega}$

Vedclass · Answer

(B) The conduction current density is given by $J_c = \sigma E$,where $E = E_0 \sin(\omega t - kx)$. Thus,the magnitude is $J_c = \sigma E_0$.The displacement current density is given by $J_d = \varepsilon \varepsilon_0 \frac{\partial E}{\partial t}$.Since $E = E_0 \sin(\omega t - kx)$,we have $\frac{\partial E}{\partial t} = E_0 \omega \cos(\omega t - kx)$.Thus,the magnitude of displacement current density is $J_d = \varepsilon \varepsilon_0 E_0 \omega$.The ratio of conduction current density to displacement current density is $\frac{J_c}{J_d} = \frac{\sigma E_0}{\varepsilon \varepsilon_0 E_0 \omega} = \frac{\sigma}{\varepsilon \varepsilon_0 \omega}$.

$A$ plane electromagnetic wave of angular frequency $\omega$ propagates in a poorly conducting medium of conductivity $\sigma$ and relative permittivity $\varepsilon$. Find the ratio of conduction current density and displacement current density in the medium.

Similar Questions

Write Maxwell's equations.

Which is the missing term in Ampere's circuital law?

Maxwell's equations describe the fundamental laws of

You are given a $2 \,\mu F$ parallel plate capacitor. How would you establish an instantaneous displacement current of $1 \, mA$ in the space between its plates?

Who discovered for the first time that a changing electric field can produce a magnetic field?

Vedclass Test Series

Exam Paper Generator

Online Exam Module